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-7x^2-6x+9x=-3
We move all terms to the left:
-7x^2-6x+9x-(-3)=0
We add all the numbers together, and all the variables
-7x^2+3x+3=0
a = -7; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·(-7)·3
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{93}}{2*-7}=\frac{-3-\sqrt{93}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{93}}{2*-7}=\frac{-3+\sqrt{93}}{-14} $
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